The two harmonics of a tube closed at on...

The two harmonics of a tube closed at one end and open at other are 200 Hz and 260 Hz. What is the funamental frequency of the system?

10 Hz

20 Hz

30Hz

40 Hz

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The correct Answer is:

Two successive frequencies of closed pipe
`(nv)/(rl)=220` .....(i)
`((n+2)v)/(4I)=260` ...... (ii)
Dividing (ii) by (i) , we get
`(n+2)/(n)=(260)/(220)=(13)/(11)`
` 11n+22=13n`
` n=11 `
So, ` 11 (v)/(4I)=220`
`(v)/(4l)=20`
So fundamental frequency is 20 Hz .

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