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The resistance of a wire is 'R' ohm. If ...

The resistance of a wire is 'R' ohm. If it is melted and stretched to `n` times its origianl length, its new resistance will be
(a) `nR` (b) `R/n` (c) `n^(2)R` (d) `R/(n^(2))`

A

nR

B

`(R)/(n)`

C

`n^(2)R`

D

`(R)/(n^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
`(R_(2))/(R_(1))=(l_(2)^(2))/(l_(1)^(2))`
`=(n^(2)l_(1)^(2))/(l_(1)^(2))`
`(R_(2))/(R_(1))=n^(2)`
` R_(1)=n^(2)R_(1)`
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