Home
Class 12
CHEMISTRY
Concentration of the Ag^(+) ions in a s...

Concentration of the `Ag^(+) `ions in a saturated solution of `Ag_2C_2O_4` is ` 2.2 xx 10 ^(-4) " mol " L^(-1) ` , Solubility product of `Ag_2C_2O_4` is
(a)` 2.42 xx 10^(-8)`
(b)` 2.66 xx 10^(-12)`
(c)` 4.5 xx 10^(-11)`
(d)` 5.3 xx 10 ^(-12)`

A

`2.42xx10^(-8)`

B

`2.66 xx 10^(-12)`

C

`4.5 xx 10^(-11)`

D

` 5.3 xx 10^(-12)`

Text Solution

Verified by Experts

The correct Answer is:
D

`Ag_(2)C_(2)O_(4)(s) iff 2 underset(2s)(Ag^(+)(aq))+underset(s)(C_(2)O_(4)^(2-)(aq))`
`K_(sp)=[Ag^(+)]^(2)[C_(2)O_(4)^(2-)]`
`[Ag^(+)]=2.2xx10^(-4)M`
`:. [C_(1)O_(2)^(1-)]=(2.2xx10^(-2))/(2)M=1.1xx10^(-2) M`
`:. K_(SP)=(2.2 xx 10^(-4))^(2)(1.1xx10^(-4))`
`=5.324 xx 10^(-12)`
Promotional Banner

Similar Questions

Explore conceptually related problems

The concentration of Ag^(o+) ions in a saturated solution of Ag_(2)C_(2)O_(4) is 2.2 xx 10^(-4)M . Calculate the solubility product of Ag_(2)C_(2)O_(4)

A saturated solution of Ag_(2)SO_(4) is 2.5 xx 10^(-2)M . The value of its solubility product is

The concentration of Ag^(o+) ions in a saturated solution of Ag_(2)C_(2)O_(4) is 2.0 xx 10^(-4)M . Calculate the solubility of Ag_(2)C_(2)O_(4) in a solution which is 0.01M in H_(2)C_(2)O_(4) .

The solubility of a saturated solution of calcium fluoride is 2xx10^(-4) mol/L. Its solubility product is

At 20^(@)C , the Ag^(+) ion concentration in a saturated solution Ag_(2)CrO_(4) is 1.5 x10^(-4) mol // litre. At 20^(@)C , the solubility product of Ag_(2)CrO_(4) would be

At 25^oC , if the concentration of Ag^+ ion is 1.5xx10^-4 mol/L in the saturated solution of Ag_2Cr_2O_7 , then solubility product of Ag_2Cr_2O_7 is

pH of a saturated solution of Ba(OH)_2 is 12. The value of solubility product K_(sp) " of " Ba(OH)_2 is (a) 3.3 xx 10^(-7) (b) 5.0 xx 10^(-7) (c) 4.0 xx 10^(-6) (d) 5.0 xx 10^(-6)

A beer has a pH of 4.30. What is the [H_(3)O^(+)] ? (a) 3.0xx10^(-4) (b) 2.0xx10^(-4) (c) 2.0xx10^(5) (d) 5.0xx10^(-5)

Simplify : (4xx10^(-2))-(2.5xx10^(-3))

The conductivity of a saturated solution of Ag_(3)PO_(4) is 9 xx 10^(-6) S m^(-1) and its equivalent conductivity is 1.50 xx 10^(-4) Sm^(2) "equivalent"^(-1) . Th K_(sp) of Ag_(3)PO_(4) is:-