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When the light of frequency 2v(0) (where...

When the light of frequency `2v_(0)` (where `v_(0)` is threshold frequency), is incident on a metal plate, the maximum velocity of electrons emitted plate, the maximum of the incident radiation is increased to `5v_(0)`, the maximum velocity of electrons emitted from the same plate is `v_(2)`. The ratio of `v_(1)` to `v_(2)` is

A

`4:1`

B

`1:4`

C

`1:2`

D

`2:1`

Text Solution

Verified by Experts

The correct Answer is:
C
`E=W_(0)+(1)/(2)mv^(2)`
`h(2v_(0))=hv_(0)+(1)/(2)mv_(1)^(2)`
`hv_(0)=(1)/(2)mv_(1)^(2)" "(i)`
`h(5v_(0))=hv_(0)+(1)/(2)mv_(2)^(2)`
`4hv_(0)=(1)/(2)mv_(2)^(2)`
Divide (i) by (ii),
`(1)/(4)=(v_(1)^(2))/(v_(2)^(2))`
`(v_(1))/(v_(2))=(1)/(2)`
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