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In the circuit shown in the figure, the ...

In the circuit shown in the figure, the input voltage `V_(i)` is 20V, `V_(BE)=0` and `V_(CE) = 0`. The values of `I_(B)`, `I_(C)` and `beta` are given by

A

`I_(B)=20, muA, I_(C)=5 mA, beta=250`

B

`I_(B)=25 muA, I_(C)=5 mA, beta=200`

C

`I_(B)=40 mu A, I_(C)=10 mA, beta=250`

D

`I_(B)=40 muA, I_(C)=5 mA, beta=125`

Text Solution

Verified by Experts

The correct Answer is:
D
`V_(BE)=0`
`V_(CE)=0`
`V_(b)=0`

`I_(C)=((20-0))/(4xx10^(3))`
`I_(C)=5xx10^(-3)=5 mA`
`V_(i)=V_(BE)+I_(B)R_(B)`
`V_(i)=0+I_(B)R_(B)`
`20=I_(B)xx500xx10^(3)`
`I_(B)=(20)/(500xx10^(3))=40 muA`
`beta=(I_(C))/(I_(b))=(25xx10^(-3))/(40xx10^(-6))=125`
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