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A pendulum is hung from the roof of a su...

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator.The acceleratiopn of the bovb of the pendulum is `20 m//s^(2)` at a distance of 5 m from the mean position.The time period of oscillation is

A

2 s

B

`pi` s

C

`2pi` s

D

1s

Text Solution

Verified by Experts

The correct Answer is:
B
`|a|=omega^(2)y`
`implies 20=omega^(2)(5)`
`implies omega=2` rad/s
`T=(2pi)/(omega)=(2pi)/(2)=pi s`
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