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A block of mass m is placed on a smooth ...

A block of mass m is placed on a smooth inclined wedge ABC of inclination `theta`as shown in the figure .The wedge is given an acceleration `alpha` towards the righjt .The relation between `alpha`and `theta` for the block to remain stationary on the wedge is

A

`a= g cos theta`

B

`a=(g)/(sin theta)`

C

`a=(g)/(cosec theta)`

D

`a=g tan theta`

Text Solution

Verified by Experts

The correct Answer is:
D

In non-inertial frame,
N `sin theta=ma " "…(i)`
N `cos theta=mg" "…(ii)`
`tan theta =(a)/(g)`
`a=gtan theta`
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