Home
Class 12
PHYSICS
The moment of the force ,F = 4hati+5hatj...

The moment of the force ,`F = 4hati+5hatj-6hatK at (2,0-3) about the point (2,-2,-2), is given by

A

`-7hati-8hatj-4hatk`

B

`-6hati-hatj-8hatk`

C

`-8hati-4hatj-7hatk`

D

`-7hati-4hatj-8hatk`

Text Solution

Verified by Experts

The correct Answer is:
D


`hat tau=(hatr-hatr_(0))xxhatf" "(i)`
`hatr-hatr_(0)=(2hati+0hatj-3hatk)-(3hati-2hatj-2hatk)`
`=0hati+2hatj-hatk`
`hattau=|{:(hati,hatj,hatk),(0,2,-1),(4,5,-6):}|=-7hati-4hatj-8hatk`
Promotional Banner

Similar Questions

Explore conceptually related problems

The moment of the force, vec F = 4 hati + 5 hat j - 6 hat k at (2, 0 , - 3) . About the point (2, - 2, -2) is given by

The position vector of a point is (3hati-2hatj+6hatk)m . The i^(th) component of torque of force (2hati+3hatj-6hatk)N acting at the point about origin in (Nm) is

The moment of the couple formed by the forces 5hati +hatj and -5hati - hatk acting at the points (9 ,-1,2) and ( 3,-2,1) respectively, is

Find the moment about (1,-1,-1) of the force 3hati+4hatj-5hatk acting at (1,0,-2)

What is the torque of the force vecF=(2hati+3hatj+4hatk)N acting at the point vecr=(2hati+3hatj+4hatk)m about the origin? (Note: Tortue, vectau=vecrxxvecF )

IF the force represented by 3hatj +2hatk is acting through the point 5hati +4hatj -3hatk , then its moment about th point (1,3,1) is

The torque of force F =(2hati-3hatj+4hatk) newton acting at the point r=(3hati+2hatj+3hatk) metre about origin is (in N-m)

Find the torque of a force F=a(hati+2hatj+3hatk) N about a point O. The position vector of point of application of force about O is r=(2hati+3hatj-hatk) m .

The moment of the couple consisting of the force through the point 2hati -3hatj -hatk is

A force F= 2hati+3hatj-hatk acts at a point (2,-3,1). Then magnitude of torque about point (0,0,2) will be