In the reaction

The electrophile involved is
a.Dichloromethyl anion `(overset(o+)(C)HCl_(2))`
b.Formly cation `(overset(o+)(C)HO)`
c.Dichloromethyl cation `(overset(o+)(C)HCl_(2))`
d.Dichlorocarbene `(":CC"l_(2))`

Options

A. Dichloromethyl anion `(overset(o+)(C)HCl_(2))`
B. Formly cation `(overset(o+)(C)HO)`
C. Dichloromethyl cation `(overset(o+)(C)HCl_(2))`
D. Dichlorocarbene `(":CC"l_(2))`

Answer

D

Explanation

It is Reimer-Tiemann reaction, The electrophile formed is :`"CC"l_(2)` (Dichlorocarbene) according to the following reaction
`CHCl_(3)+OH^(-) hArr overset(Θ)overset(**)(C)Cl_(3)+H_(2)O`
`overset(Θ)overset(**)(C)Cl_(3) to :underset("Electrophile")("CCl"_(2))+Cl^(-)`