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Consider the following species : CN^(...

Consider the following species :
` CN^(+) ,CN^(-) ,NO and CN`
Which one of these will have the highest bond order?

A

`CN^(+)`

B

`CN^(-)`

C

`NO`

D

`CN`

Text Solution

Verified by Experts

The correct Answer is:
B
`NO: (sigma1s)^(2),(sigma^(**)1s)^(2),(sigma^(**)2s)^(2),(sigma2P_(z))^(2)`,
`(pi2P_(x))^(2)=(pi2P_(y))^(2),(pi^(**)2P_(x))^(1)=(pi^(**)2P_(y))^(0)`
`BO=(10-5)/(2)=2.5`
`CN^(-): (sigma1s)^(2),(sigma^(**)1s)^(2),(sigma2s)^(2),(sigma^(**)2s)^(2),(pi2P_(x))^(2)`
`=(pi2P_(y))^(2),(sigma2P_(z))^(2)`
`BO=(10-4)/(2)=3`
CN :` (sigma1s)^(2),(sigma^(**)1s)^(2),(sigma2s)^(2),(sigma^(**)2s)^(2),(pi2P_(x))^(2)`
`=(pi2P_(y))^(2),(sigma2P_(z))^(1)`
`BO=(9-4)/(2)=2.5`
`CN^(+): (sigma1s)^(2),(sigma^(**)1s)^(2),(sigma2s)^(2),(sigma^(**)2s)^(2),(pi2P_(x))^(2)`
`=(pi2P_(y))^(2)`
`BO=(8-4)/(2)=2`
Hence , option (2) should be the right answer.
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