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Two coils have the mutual inductance of ...

Two coils have the mutual inductance of 0.05 H. The current changes in the first coil as `I=I_(0)sin omegat`, where `I_(0)=1A` and `omega=100pi"rad/s"`. The maximum emf induced in secondary coil is

A

`4pi`

B

`3pi`

C

`2pi`

D

`pi`

Text Solution

Verified by Experts

The correct Answer is:
D
`e=M(di)/(dt)=0.005 xxd/dt(i_(0)sinomegat)`
`=0.005i_(0)omegacosomegat= e_(0)cosomegat`
`therefore" "e_(max)=0.005xx2xx100pi=pi`
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