Number of isomers of `[Pt(NH_(3))_(4)][CuCI_(4)]` complex are :

Options

A. 2
B. 3
C. 4
D. 5

Answer

To determine the number of isomers of the complex \([Pt(NH_3)_4][CuCl_4]\), we will analyze the coordination isomerism that can occur due to the presence of different ligands in the coordination spheres of platinum and copper.

### Step-by-Step Solution:

1. **Identify the Coordination Complex**:
The complex consists of a cationic part \([Pt(NH_3)_4]^{2+}\) and an anionic part \([CuCl_4]^{2-}\). Here, platinum is coordinated to four ammonia ligands, and copper is coordinated to four chloride ligands.

2. **Understanding Coordination Isomerism**:
Coordination isomerism occurs when ligands can be exchanged between the cationic and anionic parts of the complex. In this case, we can interchange ammonia and chloride ions between the two coordination spheres.

3. **List Possible Isomers**:
- **Isomer 1**: \([Pt(NH_3)_4][CuCl_4]\) (original structure)
- **Isomer 2**: \([Pt(NH_3)_3Cl][CuCl_3(NH_3)]\) (3 ammonia and 1 chloride on platinum, 1 ammonia and 3 chlorides on copper)
- **Isomer 3**: \([Pt(NH_3)_2Cl_2][CuCl_2(NH_3)_2]\) (2 ammonia and 2 chlorides on platinum, 2 ammonia and 2 chlorides on copper) - **Not possible** due to charge balance.
- **Isomer 4**: \([Pt(NH_3)Cl_3][CuCl(NH_3)_3]\) (1 ammonia and 3 chlorides on platinum, 3 ammonia and 1 chloride on copper)
- **Isomer 5**: \([PtCl_4][Cu(NH_3)_4]\) (all chlorides on platinum and all ammonia on copper)

4. **Count Valid Isomers**:
From the above possibilities, we can count:
- Isomer 1: Valid
- Isomer 2: Valid
- Isomer 3: Not valid (charge imbalance)
- Isomer 4: Valid
- Isomer 5: Valid

Therefore, the total number of valid isomers is **4**.

### Final Answer:
The number of isomers of the complex \([Pt(NH_3)_4][CuCl_4]\) is **4**.