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Maximum oxidation state will be of :...

Maximum oxidation state will be of :

A

La

B

Gd

C

Eu

D

Am

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The correct Answer is:
To determine the maximum oxidation state of the given elements, we will analyze the electronic configurations and the common oxidation states of each element. 1. **Lanthanum (La)**: - Electronic configuration: [Xe] 5d¹ 6s² - The maximum oxidation state of Lanthanum is +3. This is because it can lose its 3 outermost electrons (2 from 6s and 1 from 5d). 2. **Gadolinium (Gd)**: - Electronic configuration: [Xe] 4f⁷ 5d¹ 6s² - The maximum oxidation state of Gadolinium is also +3. Similar to Lanthanum, it can lose 3 electrons (2 from 6s and 1 from 5d). 3. **Europium (Eu)**: - Electronic configuration: [Xe] 4f⁷ 6s² - The maximum oxidation state of Europium is +3 as well. It can lose 3 electrons (2 from 6s and 1 from 4f). 4. **Americium (Am)**: - Electronic configuration: [Rn] 5f⁷ 7s² - The maximum oxidation state of Americium is +6. Americium can lose all 7 outermost electrons (2 from 7s and 5 from 5f). After analyzing the oxidation states, we find that the maximum oxidation state is for Americium (Am), which is +6. **Final Answer**: The maximum oxidation state will be of Americium (Am), which is +6. ---
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