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The IUPAC name of [Co(NH(3))(3)CIBrNO(2)...

The IUPAC name of `[Co(NH_(3))_(3)CIBrNO_(2)]` will be :

A

Triaminebromochloronitrocobaltate (III)

B

Triaminebromochloronitrocobalt (III)

C

Triaminebromonitrochlorocobalt (III)

D

Triaminenitrochlorocobalt (III)

Text Solution

AI Generated Solution

The correct Answer is:
To determine the IUPAC name of the coordination compound \([Co(NH_3)_3ClBrNO_2]\), we will follow these steps: ### Step 1: Determine the oxidation state of the central metal ion (Co) - Let the oxidation state of cobalt be \(x\). - The ligands present are: - Ammonia \((NH_3)\) which is a neutral ligand (0 charge). - Chloride \((Cl^-)\) which has a charge of -1. - Bromide \((Br^-)\) which has a charge of -1. - Nitrite \((NO_2^-)\) which also has a charge of -1. The overall charge of the complex is neutral (0). Therefore, we can set up the equation: \[ x + 0 + (-1) + (-1) + (-1) = 0 \] \[ x - 3 = 0 \implies x = +3 \] Thus, the oxidation state of cobalt is +3. ### Step 2: Identify the ligands and their names - The ligands in the compound are: - \(NH_3\) (ammine) - \(Cl^-\) (chloro) - \(Br^-\) (bromo) - \(NO_2^-\) (nitro) ### Step 3: Arrange the ligands in alphabetical order When naming the ligands, we consider the alphabetical order based on their names: 1. Amine (ammine) - starts with 'A' 2. Bromo - starts with 'B' 3. Chloro - starts with 'C' 4. Nitro - starts with 'N' In alphabetical order, we have: - Ammine (3 times, hence "triamine") - Bromo - Chloro - Nitro ### Step 4: Combine the names of the ligands with the central metal ion The name of the complex will be constructed as follows: - Start with the ligands in alphabetical order: "triamine", "bromo", "chloro", "nitro". - Then, name the central metal ion (cobalt) followed by its oxidation state in Roman numerals. Thus, the full name becomes: \[ \text{Triamine Bromo Chloro Nitro Cobalt(III)} \] ### Final IUPAC Name The IUPAC name of the compound \([Co(NH_3)_3ClBrNO_2]\) is: **Triamine Bromo Chloro Nitro Cobalt(III)**
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