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If the power dissipated in 5Omega is 20 ...

If the power dissipated in `5Omega` is 20 W then power dissipated in `4Omega` is -

A

4W

B

6W

C

10W

D

20W

Text Solution

Verified by Experts

The correct Answer is:
A
`P=VI=V^2//R,` voltage constant

` P prop 1/R`
then power in `10Omega` will be 10W when I constant then
`P=I^2R`
`P prop R`
`P'/10=4/10 implies P'=4W`
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