Home
Class 12
PHYSICS
Two conducting slabs of heat conductivit...

Two conducting slabs of heat conductivity `K_1 " and " K_2` are joined as shown in fig. The temp. at ends of the slabs are `theta_1 " and " theta_2 (theta_1 gt theta_2)` the, final temp. `(theta_m)` of junction is :

A

`(K_1theta_1+K_2theta_2)/(K_1+K_2)`

B

`(K_1theta_2+K_2theta_1)/(K_1+K_2)`

C

`(K_1theta_2-K_2theta_1)/(K_1+K_2)`

D

None

Text Solution

Verified by Experts

The correct Answer is:
A
`Q=(K_1A(theta_1-theta)t)/(d)=(K_2A(theta-theta_2)t)/(d)`
`Or " " K_1theta_1-K_1theta=K_2theta-K_2theta_2`
`K_1theta_1+K_2theta_2=K_1theta+K_2theta`
`theta = (K_1theta_1+K_2theta_2)/(K_1+K_2)`
Promotional Banner

Similar Questions

Explore conceptually related problems

Prove that 1 + tan 2 theta tan theta = sec 2 theta .

If "tan" 2 theta "tan" theta =1, "then" theta =

Solve sin^2 theta tan theta+cos^2 theta cot theta-sin 2 theta=1+tan theta+cot theta

Solve tan theta + tan 2 theta + tan theta * tan 2 theta * tan 3 theta=1

Two materials having coefficients of thermal conductivity '3k' and 'k' and thickness 'd' and '3d' respectively, are joined to form a slab as shown in the figures. The temperatures of the outer surfaces are theta_(2) and theta_(1) respectively (theta_(2) gt theta_(2)) . The temperature at the interface is :

Prove that sin(2theta)/(1-cos2theta)=cot theta

Prove that cos theta (tan theta +2) (2tan theta +1) = 2 sec theta + 5 sin theta

(sin theta + sin 2 theta)/( 1 + cos theta + cos 2 theta) = tan theta.

Prove that (1 - cos 2 theta)/( sin 2 theta) = tan theta.

Two identical rods are made of different materials whose thermal conductivities are K_(1) and K_(2) . They are placed end to end between two heat reservoirs at temperatures theta_(1) and theta_(2) . The temperature of the junction of the rod is