Mole ratio of `H_2` and `O_2` gas is 8 : 1 what will be the ratio of wt. :

Options

A. `1:1`
B. `2:1`
C. `4:1`
D. `1:2`

Answer

To solve the problem of finding the weight ratio of \( H_2 \) and \( O_2 \) gases given their mole ratio of 8:1, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Mole Ratio**:
The mole ratio of \( H_2 \) to \( O_2 \) is given as 8:1. This means for every 8 moles of \( H_2 \), there is 1 mole of \( O_2 \).

2. **Determine Molar Masses**:
- The molar mass of \( H_2 \) (hydrogen gas) is \( 2 \, \text{g/mol} \) (since each hydrogen atom has a mass of approximately 1 g/mol and there are 2 hydrogen atoms).
- The molar mass of \( O_2 \) (oxygen gas) is \( 32 \, \text{g/mol} \) (since each oxygen atom has a mass of approximately 16 g/mol and there are 2 oxygen atoms).

3. **Calculate the Total Mass for Each Gas**:
- The mass of \( H_2 \) can be calculated using the formula:
\[ \text{Mass of } H_2 = \text{Number of moles} \times \text{Molar mass} \]
For \( H_2 \):
\[ \text{Mass of } H_2 = 8 \, \text{moles} \times 2 \, \text{g/mol} = 16 \, \text{g} \]
- The mass of \( O_2 \) can be calculated similarly:
\[ \text{Mass of } O_2 = 1 \, \text{mole} \times 32 \, \text{g/mol} = 32 \, \text{g} \]

4. **Find the Weight Ratio**:
Now, we can find the weight ratio of \( H_2 \) to \( O_2 \):
\[ \text{Weight ratio} = \frac{\text{Mass of } H_2}{\text{Mass of } O_2} = \frac{16 \, \text{g}}{32 \, \text{g}} = \frac{1}{2} \]

5. **Conclusion**:
Therefore, the weight ratio of \( H_2 \) to \( O_2 \) is \( 1:2 \).

### Final Answer:
The ratio of weights of \( H_2 \) to \( O_2 \) is \( 1:2 \).