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A Carnot engine whose sink is at 300K ha...

A Carnot engine whose sink is at `300K` has an efficiency of `40%`. By how much should the temperature of source be increased so as to increase its efficiency by `50%` of original efficiency.

A

275 K

B

325 K

C

250 K

D

380 K

Text Solution

Verified by Experts

The correct Answer is:
C
`eta = 1 -(T_(2))/T_(1)implies 1-(300)/(T_(1)) =0.4 implies T_(1) =500K`
now `eta in=0.4+0.4xx(50)/(100)=0.6`
therefore 0.6=1-`(300)/(500+DeltaT)`
implies 500 +`DeltaT=750impliesDeltaT=250K`
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