The momentum of a photon of energy 1MeV ...

The momentum of a photon of energy `1MeV "in" kg m//s`, will be

A

0.33 × `10^(6)`

B

` 7 × 10^(–24)`

C

`10^(–22)`

D

` 5× 10^(–22)`

Verified by Experts

The correct Answer is:

D

For a photon E=pc
`impliesp=(E)/(c)=(10^(6)xx1.6xx10^(-19))/(3xx10^(8))=5.33xx10^(-22)`
`kgms^(-1)`

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