Home
Class 12
PHYSICS
Two sound waves with wavelengths 5.0 m a...

Two sound waves with wavelengths `5.0 m` and `5.5 m` respectively, each propagates in a gas with velocity `330m//s` We expect the following number of beats per second:

A

12

B

0

C

1

D

6

Text Solution

Verified by Experts

The correct Answer is:
D
Number of beats per second
`=(v)/(lambda_(1))-(v)/(lambda_(2))` `=330((1)/(5)-(1)/(5.5))=66-60=6`
Promotional Banner

Similar Questions

Explore conceptually related problems

Two sound waves of wavelength 1 m and 1.01 m in a gas produce 10 beats in 3 s. The velocity of sound in the gas is

Two notes of wavelength 2.08 m and 2.12 m produce 180 beats per minute in a gas, Find the velocity of sound in the gas.

Two sound waves of wavelength 1 m and 1.02 m produces 16 beats in 2 s in a medium then the velocity of the sound in that medium is

two waves of wavelengths 2 m and 2.02 m respectively, moving with the same velocity superpose to produce 2 beats per second. The velocity of the wave is

two waves of wavelength 100 cm and 102 cm produce 12 beats per second having same velocity. the velocity of each wave is

Two sound waves of wavelengths 98cm and 100cm arrive at the same point,from two different source.The number of beats heard (per second) is (speed of sound is 392m/s)

The wavelength of two sound waves are 49 cm and 50 cm , respectively . If the room temperature is 30^(@) C , then the number of beats produced by them is approximately (velocity of sound in air at 30 ^(@) C = 332 m//s )

Two waves of wavelengths 99 cm and 100 cm produce 4 beats per second. Velocity of sound in the medium is

Two open organ pipes of lengths 60 cm and 60.5 cm produce 2 beats per second. Calculate the velocity of sound in air.?

Two sound sources emitting sound each of wavelength lambda are fixed at a given distance apart. A listener moves with a velocity u along the line joining the two sources. The number of beats heard by him per second is