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A unifrom rod of length l and mass m is ...

A unifrom rod of length `l` and mass `m` is free to rotate in a vertical plane about `A`, Fig. The rod initially in horizontal position is released. The initial angular acceleration of the rod is `(MI "of rod about" A "is" (ml^(2))/(3))`

A

`(3g)/(2l)`

B

`(2l)/(3g)`

C

`(3g)/(2l^(2))`

D

`mg l/2`

Text Solution

Verified by Experts

The correct Answer is:
A

Here `tau=Ia
implies(mg)((l)/(2))=((ml^(2))/(3))(alpha)=(3g)/(2l)`
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