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for the reaction, 2A + B rarr 3C + D, wh...

for the reaction, `2A + B rarr 3C + D`, which of the following does not express the reaction rate

A

`-(d[C])/(3dt)`

B

`-(d[B])/(dt)`

C

`(d[D])/(dt)`

D

`-(d[A])/(2dt)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which option does not express the reaction rate for the reaction \(2A + B \rightarrow 3C + D\), we need to analyze the rate expressions based on the stoichiometry of the reaction. ### Step-by-Step Solution: 1. **Identify the Reaction Components**: The reaction is given as: \[ 2A + B \rightarrow 3C + D \] Here, \(A\) and \(B\) are reactants, and \(C\) and \(D\) are products. 2. **Understand the Stoichiometric Coefficients**: - The stoichiometric coefficient of \(A\) is 2. - The stoichiometric coefficient of \(B\) is 1. - The stoichiometric coefficient of \(C\) is 3. - The stoichiometric coefficient of \(D\) is 1. 3. **Write the Rate Expressions**: The rate of a reaction can be expressed in terms of the change in concentration of reactants and products over time. The general form is: \[ \text{Rate} = -\frac{1}{\text{coefficient}} \frac{d[\text{reactant}]}{dt} = \frac{1}{\text{coefficient}} \frac{d[\text{product}]}{dt} \] - For \(A\): \[ \text{Rate} = -\frac{1}{2} \frac{d[A]}{dt} \] - For \(B\): \[ \text{Rate} = -\frac{1}{1} \frac{d[B]}{dt} = -\frac{d[B]}{dt} \] - For \(C\): \[ \text{Rate} = \frac{1}{3} \frac{d[C]}{dt} \] - For \(D\): \[ \text{Rate} = \frac{1}{1} \frac{d[D]}{dt} = \frac{d[D]}{dt} \] 4. **Evaluate Each Option**: - **Option D**: \(-\frac{dA}{2dt}\) - This is correct for \(A\). - **Option C**: \(\frac{dD}{dt}\) - This is correct for \(D\). - **Option B**: \(-\frac{dB}{dt}\) - This is correct for \(B\). - **Option A**: \(-\frac{dC}{3dt}\) - This is incorrect because \(C\) is a product and should have a positive sign. 5. **Conclusion**: The option that does not express the reaction rate correctly is: \[ \text{Answer: Option A: } -\frac{dC}{3dt} \]
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