The major organic product in the reaction
`CH_(3)-O-CH(CH_(3))_(2)+HIrarr` product is

Options

A. CH3OH + (CH3)2CHI
B. `ICH_(2)OCH(CH_(3))_(2)`
C. `CH_(3)Ounderset(I)underset(|)(C)(CH_(3))_(2)`
D. `CH_(3)CHO`

Explanation

To find the major organic product of the reaction between the ether \( CH_3-O-CH(CH_3)_2 \) and hydrogen iodide (HI), we can follow these steps:

### Step 1: Identify the Reactants
The reactant is an ether, specifically \( CH_3-O-CH(CH_3)_2 \). It consists of a methyl group (\( CH_3 \)) and an isopropyl group (\( CH(CH_3)_2 \)) connected by an oxygen atom.

### Step 2: Mechanism of Reaction
The reaction proceeds via an SN1 mechanism. This is because the ether can form a stable secondary carbocation when it reacts with HI. The oxygen atom in the ether has lone pairs that can interact with the hydrogen from HI, leading to the formation of a carbocation.

### Step 3: Protonation of the Ether
The oxygen atom in the ether will protonate by accepting a hydrogen ion (H⁺) from HI. This results in the formation of an oxonium ion:
\[ CH_3-OH^+-CH(CH_3)_2 \]

### Step 4: Carbocation Formation
Once the ether is protonated, the bond between the oxygen and the isopropyl group can break, leading to the formation of a secondary carbocation:
\[ CH_3^+-C(CH_3)_2 \]

### Step 5: Nucleophilic Attack
Now, the iodide ion (I⁻) from HI can attack the carbocation. Since the carbocation is secondary, it is relatively stable, and the iodide ion will preferentially attack this positive charge.

### Step 6: Formation of the Product
The final product formed after the nucleophilic attack will be:
\[ CH_3-CH(CH_3)_2-I \]
This product is 1-iodo-2-methylpropane.

### Final Answer
The major organic product of the reaction is:
\[ CH_3-CH(CH_3)_2-I \]