The correct order regarding the electronegativity of hybrid orbitals of carbon is:-

Options

A. `sp gt sp^(2) lt sp^(3)`
B. `sp gt sp^(2) gt sp^(3)`
C. `sp lt sp^(2) gt sp^(3)`
D. `sp lt sp^(2) lt sp^(3) `

Answer

To determine the correct order regarding the electronegativity of hybrid orbitals of carbon (sp, sp², sp³), we can follow these steps:

### Step 1: Understand Hybridization
Hybridization is the mixing of atomic orbitals to form new hybrid orbitals. For carbon, the types of hybridization are sp, sp², and sp³.

### Step 2: Identify the Percent s Character
The percent s character in each type of hybrid orbital can be calculated as follows:
- **sp Hybridization**:
- In sp hybridization, there is 1 s orbital and 1 p orbital.
- Percent s character = (Number of s orbitals / Total number of orbitals) × 100
- Percent s character = (1 / 2) × 100 = 50%

- **sp² Hybridization**:
- In sp² hybridization, there is 1 s orbital and 2 p orbitals.
- Percent s character = (1 / 3) × 100 = 33.33%

- **sp³ Hybridization**:
- In sp³ hybridization, there is 1 s orbital and 3 p orbitals.
- Percent s character = (1 / 4) × 100 = 25%

### Step 3: Relate Percent s Character to Electronegativity
Electronegativity is directly proportional to the percent s character in hybrid orbitals. This means that as the percent s character increases, the electronegativity also increases.

### Step 4: Compare the Percent s Characters
From the calculations:
- sp hybridization: 50% s character
- sp² hybridization: 33.33% s character
- sp³ hybridization: 25% s character

### Step 5: Determine the Order of Electronegativity
Based on the percent s character, we can conclude:
- sp > sp² > sp³

### Final Answer
The correct order regarding the electronegativity of hybrid orbitals of carbon is:
**sp > sp² > sp³**