`CH_3CH_2CH=CH_2 overset(B_2H_6)underset(H_2O_,H_2O_2,OH^-)rarr Z`
What is Z?

Options

A. `CH_3CH_2CH_2CH_2OH`
B. `CH_3CH_2CH(OH)CH_3`
C. `CH_3CH_2CH_2CHO`
D. `CH_3CH_2CH_2CH_3`

Answer

To determine the product Z from the given reaction of butene with diborane followed by oxidation, we can follow these steps:

### Step 1: Identify the Reactants
The reactant is 1-butene (CH₃CH₂CH=CH₂) which is an alkene. The other reactant is diborane (B₂H₆).

**Hint:** Remember that alkenes undergo hydroboration when reacted with diborane.

### Step 2: Hydroboration Reaction
In the hydroboration step, diborane adds across the double bond of the alkene. This results in the formation of a trialkylborane. For 1-butene, the addition occurs in a syn fashion, leading to the formation of tri-n-butylborane (B(CH₂CH₂CH₂CH₃)₃).

**Hint:** The addition of boron occurs in a way that the boron atom attaches to the less substituted carbon of the double bond.

### Step 3: Oxidation Step
Next, the trialkylborane is oxidized in the presence of hydrogen peroxide (H₂O₂) and sodium hydroxide (NaOH). This oxidation converts the boron compound into an alcohol.

**Hint:** The oxidation of trialkylborane with H₂O₂ and NaOH leads to the formation of alcohols.

### Step 4: Determine the Product
The oxidation of tri-n-butylborane will yield butanol. Since the hydroboration reaction adds the boron to the terminal carbon, the resulting alcohol will be 1-butanol (butan-1-ol).

**Hint:** The position of the hydroxyl (-OH) group in the final alcohol product is determined by the initial addition of boron to the alkene.

### Conclusion
The final product Z is 1-butanol (butan-1-ol).

**Final Answer: Z = Butan-1-ol (CH₃CH₂CH₂CH₂OH)**