If equation `(lamda^(2)-5lamda+6)x^(2)+(lamda^(2)-3lamda+2)x+(lamda^(2)-4)=0` is satisfied by more than two values of `x`, find the parameter `lamda`.

Explanation

To solve the equation

\[ (\lambda^2 - 5\lambda + 6)x^2 + (\lambda^2 - 3\lambda + 2)x + (\lambda^2 - 4) = 0 \]

for the parameter \(\lambda\) such that it is satisfied by more than two values of \(x\), we need to analyze the coefficients of the quadratic equation.

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