The solution set of x which satisfies the equation `x^2 + (x+1)^2 = 25` where `(x)` is a least integer greater than or equal to x

Explanation

To solve the equation \( x^2 + (x+1)^2 = 25 \) where \( x \) is the least integer greater than or equal to \( x \), we will follow these steps:

### Step 1: Expand the equation
First, we expand the left-hand side of the equation:
\[ x^2 + (x+1)^2 = x^2 + (x^2 + 2x + 1) = 2x^2 + 2x + 1 \]
So, the equation becomes:
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