If `x_(1),x_(2),x_(3),.,x_(n)` are the roots of the equation `x^(n)+ax+b=0`, the value of
`(x_(1)-x_(2))(x_(1)-x_(3))(x_(1)-x_(4))…….(x_(1)-x_(n))` is

Options

A. (a) `nx_(1)+b`
B. (b) `n(x_(1))^(n-1)`
C. (c) `n(x_(1))^(n-1)+a`
D. (d) `n(x_(1))^(n-1)+b`

Explanation

To solve the problem, we need to find the value of the expression:

\[ (x_1 - x_2)(x_1 - x_3)(x_1 - x_4) \ldots (x_1 - x_n) \]

where \(x_1, x_2, \ldots, x_n\) are the roots of the polynomial equation:

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