Solve the equation: `2x^(2)-6sqrt(2)x-1=0`

Options

A. roots are rational
B. roots are irrational
C. if one root is `(p+sqrt(q))`, the other is `(-p+sqrt(q))`
D. if one roots is `(p+sqrt(q))` the other is `(p-sqrt(q))`

Explanation

To solve the equation \( 2x^2 - 6\sqrt{2}x - 1 = 0 \), we will use the quadratic formula. The quadratic formula is given by:

\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]

### Step 1: Identify the coefficients
In the equation \( 2x^2 - 6\sqrt{2}x - 1 = 0 \), we can identify the coefficients as follows:
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