If the roots of the equation `ax^(2)+bx+c=0(a!=0)` be `alpha` and `beta` and those of the equation `Ax^(2)+Bx+C=0(A!=0)` be `alpha+k` and `beta+k`.Prove that
`(b^(2)-4ac)/(B^(2)-4AC)=(a/A)^(2)`

Explanation

To prove that

\[ \frac{b^2 - 4ac}{B^2 - 4AC} = \left(\frac{a}{A}\right)^2, \]

we start with the given equations and their roots.

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