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If a x^2+(b-c)x+a-b-c=0 has unequal real...

If `a x^2+(b-c)x+a-b-c=0` has unequal real roots for all `c in R ,t h e n` `b<0 a >0`

A

`blt0lta`

B

`altoltb`

C

`bltalt0`

D

`bgtagt0`

Text Solution

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To solve the problem, we need to analyze the quadratic equation given by: \[ ax^2 + (b - c)x + (a - b - c) = 0 \] We want to determine the conditions under which this equation has unequal real roots for all \( c \in \mathbb{R} \). ### Step 1: Identify the condition for unequal real roots For a quadratic equation \( Ax^2 + Bx + C = 0 \) to have unequal real roots, the discriminant must be positive: \[ D = B^2 - 4AC > 0 \] In our case: - \( A = a \) - \( B = b - c \) - \( C = a - b - c \) ### Step 2: Calculate the discriminant The discriminant \( D \) is given by: \[ D = (b - c)^2 - 4a(a - b - c) \] Expanding this, we have: \[ D = (b^2 - 2bc + c^2) - 4a(a - b - c) \] \[ D = b^2 - 2bc + c^2 - 4a^2 + 4ab + 4ac \] ### Step 3: Rearranging the discriminant Rearranging gives us: \[ D = c^2 + (4a - 2b)c + (b^2 - 4a^2 + 4ab) \] ### Step 4: Condition for \( D > 0 \) for all \( c \) For the quadratic in \( c \) to be positive for all \( c \), the discriminant of this quadratic must be less than or equal to zero: \[ (4a - 2b)^2 - 4 \cdot 1 \cdot (b^2 - 4a^2 + 4ab) < 0 \] ### Step 5: Simplifying the condition Expanding and simplifying: \[ 16a^2 - 16ab + 4b^2 - 4b^2 + 16a^2 - 16ab < 0 \] This simplifies to: \[ 32a^2 - 32ab < 0 \] Factoring out \( 16a \): \[ 16a(2a - 2b) < 0 \] ### Step 6: Analyzing the inequality This inequality implies: 1. \( a > 0 \) and \( a < b \) (which means \( b > a > 0 \)) 2. \( a < 0 \) and \( a > b \) (which means \( b < a < 0 \)) ### Conclusion Thus, we have two cases: - \( b > a > 0 \) - \( b < a < 0 \) The options provided in the question are: - a. \( b < 0 < a \) - b. \( a < 0 < b \) - c. \( b < a < 0 \) - d. \( b > a > 0 \) From our analysis, the correct options that satisfy the conditions are: - \( b < a < 0 \) (Option C) - \( b > a > 0 \) (Option D) ### Final Answer The conditions for the quadratic equation to have unequal real roots for all \( c \in \mathbb{R} \) are: - \( b < a < 0 \) (Option C) - \( b > a > 0 \) (Option D)

To solve the problem, we need to analyze the quadratic equation given by: \[ ax^2 + (b - c)x + (a - b - c) = 0 \] We want to determine the conditions under which this equation has unequal real roots for all \( c \in \mathbb{R} \). ### Step 1: Identify the condition for unequal real roots For a quadratic equation \( Ax^2 + Bx + C = 0 \) to have unequal real roots, the discriminant must be positive: ...
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