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The number of solutions of the equation ...

The number of solutions of the equation
`sqrt(x^(2))-sqrt((x-1)^(2))+sqrt((x-2)^(2))=sqrt(5)` is

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To find the number of solutions for the equation \[ \sqrt{x^2} - \sqrt{(x-1)^2} + \sqrt{(x-2)^2} = \sqrt{5} \] we will analyze the equation step by step. ### Step 1: Rewrite the Equation We can rewrite the equation using the properties of absolute values: \[ |x| - |x-1| + |x-2| = \sqrt{5} \] ### Step 2: Consider Different Cases Since the absolute value function behaves differently depending on the value of \(x\), we will consider different cases based on the critical points \(x = 0\), \(x = 1\), and \(x = 2\). #### Case 1: \(x \geq 2\) In this case, all absolute values can be removed as positive: \[ x - (x - 1) + (x - 2) = \sqrt{5} \] \[ x - x + 1 + x - 2 = \sqrt{5} \] \[ x - 1 = \sqrt{5} \] \[ x = \sqrt{5} + 1 \] Since \(\sqrt{5} \approx 2.236\), we have \(x \approx 3.236\), which is valid for this case. #### Case 2: \(1 \leq x < 2\) In this case, we have: \[ x - (x - 1) - (x - 2) = \sqrt{5} \] \[ x - x + 1 - x + 2 = \sqrt{5} \] \[ 3 - x = \sqrt{5} \] \[ x = 3 - \sqrt{5} \] Calculating \(3 - \sqrt{5} \approx 0.764\), which is valid for this case. #### Case 3: \(0 \leq x < 1\) Here, we have: \[ x - (1 - x) - (2 - x) = \sqrt{5} \] \[ x - 1 + x - 2 = \sqrt{5} \] \[ 2x - 3 = \sqrt{5} \] \[ 2x = \sqrt{5} + 3 \] \[ x = \frac{\sqrt{5} + 3}{2} \] Calculating \(\frac{\sqrt{5} + 3}{2} \approx 2.618\), which is not valid for this case since \(x\) must be less than 1. #### Case 4: \(x < 0\) In this case, all absolute values are negative: \[ -x + (1 - x) + (2 - x) = \sqrt{5} \] \[ -x + 1 - x + 2 - x = \sqrt{5} \] \[ 3 - 3x = \sqrt{5} \] \[ 3x = 3 - \sqrt{5} \] \[ x = 1 - \frac{\sqrt{5}}{3} \] Calculating \(1 - \frac{\sqrt{5}}{3} \approx 0.254\), which is not valid for this case since \(x\) must be less than 0. ### Step 3: Summary of Solutions From the analysis of the four cases, we found valid solutions in: - Case 1: \(x = \sqrt{5} + 1\) (valid) - Case 2: \(x = 3 - \sqrt{5}\) (valid) - Case 3: No valid solution - Case 4: No valid solution Thus, we have **two valid solutions** for the original equation. ### Conclusion The number of solutions of the equation \[ \sqrt{x^2} - \sqrt{(x-1)^2} + \sqrt{(x-2)^2} = \sqrt{5} \] is **2**. ---

To find the number of solutions for the equation \[ \sqrt{x^2} - \sqrt{(x-1)^2} + \sqrt{(x-2)^2} = \sqrt{5} \] we will analyze the equation step by step. ...
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