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Solve The equation x^(2)+(2m+1)x+(2n+1...

Solve The equation
`x^(2)+(2m+1)x+(2n+1)=0`

A

Statement -1 is true, Statement -2 is true, Statement -2 is a correct explanation for Statement-1

B

Statement -1 is true, Statement -2 is true, Statement -2 is not a correct explanation for Statement -1

C

Statement -1 is true, Statement -2 is false

D

Statement -1 is false, Statement -2 is true

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \( x^2 + (2m + 1)x + (2n + 1) = 0 \), we will use the quadratic formula. The standard form of a quadratic equation is given by: \[ ax^2 + bx + c = 0 \] In our case: - \( a = 1 \) - \( b = 2m + 1 \) - \( c = 2n + 1 \) ### Step 1: Identify the coefficients We have: - \( a = 1 \) - \( b = 2m + 1 \) - \( c = 2n + 1 \) ### Step 2: Apply the quadratic formula The quadratic formula is given by: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] ### Step 3: Substitute the values of \( a \), \( b \), and \( c \) Substituting the values into the quadratic formula: \[ x = \frac{-(2m + 1) \pm \sqrt{(2m + 1)^2 - 4 \cdot 1 \cdot (2n + 1)}}{2 \cdot 1} \] ### Step 4: Simplify the expression Now, we simplify the expression inside the square root: \[ x = \frac{-(2m + 1) \pm \sqrt{(2m + 1)^2 - 4(2n + 1)}}{2} \] Calculating \( (2m + 1)^2 \): \[ (2m + 1)^2 = 4m^2 + 4m + 1 \] Now substituting this back into the equation: \[ x = \frac{-(2m + 1) \pm \sqrt{4m^2 + 4m + 1 - 8n - 4}}{2} \] This simplifies to: \[ x = \frac{-(2m + 1) \pm \sqrt{4m^2 + 4m - 8n - 3}}{2} \] ### Step 5: Final expression for \( x \) Thus, the solutions for \( x \) can be expressed as: \[ x = \frac{-(2m + 1) \pm \sqrt{4m^2 + 4m - 8n - 3}}{2} \]

To solve the equation \( x^2 + (2m + 1)x + (2n + 1) = 0 \), we will use the quadratic formula. The standard form of a quadratic equation is given by: \[ ax^2 + bx + c = 0 \] In our case: - \( a = 1 \) ...
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