If `lamda` be the number of 3-digit numbers are of the form xyz with `x lt y, z le y and x ne0`, the value of `(lamda)/(30)` is

Explanation

To solve the problem, we need to find the number of 3-digit numbers of the form xyz such that \( x < y \), \( z \leq y \), and \( x \neq 0 \). We will denote this count as \( \lambda \) and then compute \( \frac{\lambda}{30} \).

### Step-by-Step Solution:

1. **Identify the Range for y:**
Since \( y \) must be greater than \( x \) and can take values from 2 to 9 (as \( x \) cannot be 0), we can set:
\[
y = n \quad \text{where} \quad n \in \{2, 3, 4, 5, 6, 7, 8, 9\}
...