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The number of words of that can be made ...

The number of words of that can be made by writing down the letters of the word CALCULATE such that each word starts and ends with a consonant, is

A

`(3)/(2)(7)!`

B

`2(7)!`

C

`(5)/(2)(7)!`

D

`3(7)!`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the number of words that can be formed from the letters of the word "CALCULATE," such that each word starts and ends with a consonant, we can follow these steps: ### Step 1: Identify the consonants and vowels in the word "CALCULATE." - The consonants are: C, L, C, L, T (5 consonants) - The vowels are: A, U, A, E (4 vowels) ### Step 2: Determine the total number of letters. The total number of letters in "CALCULATE" is 9. ### Step 3: Identify the possible consonants for the first and last positions. The consonants that can be used to start and end the word are C, L, and T. ### Step 4: Calculate the cases based on different consonant combinations for the first and last letters. #### Case 1: Starts with C and ends with C. - The arrangement will look like: C _ _ _ _ _ _ _ C - We have 7 positions left to fill with the remaining letters: L, L, T, A, U, A (total of 7 letters). - The number of arrangements is given by: \[ \frac{7!}{2! \cdot 2!} = \frac{5040}{4} = 1260 \] #### Case 2: Starts with L and ends with L. - The arrangement will look like: L _ _ _ _ _ _ _ L - The remaining letters are: C, C, T, A, U, A (total of 7 letters). - The number of arrangements is given by: \[ \frac{7!}{2! \cdot 2!} = \frac{5040}{4} = 1260 \] #### Case 3: Starts with C and ends with T. - The arrangement will look like: C _ _ _ _ _ _ _ T - The remaining letters are: L, L, C, A, U, A (total of 7 letters). - The number of arrangements is given by: \[ \frac{7!}{2! \cdot 2!} = \frac{5040}{4} = 1260 \] #### Case 4: Starts with T and ends with C. - The arrangement will look like: T _ _ _ _ _ _ _ C - The remaining letters are: L, L, C, A, U, A (total of 7 letters). - The number of arrangements is given by: \[ \frac{7!}{2! \cdot 2!} = \frac{5040}{4} = 1260 \] #### Case 5: Starts with T and ends with L. - The arrangement will look like: T _ _ _ _ _ _ _ L - The remaining letters are: C, C, L, A, U, A (total of 7 letters). - The number of arrangements is given by: \[ \frac{7!}{2! \cdot 2!} = \frac{5040}{4} = 1260 \] ### Step 5: Sum all the cases. The total number of arrangements is: \[ 1260 + 1260 + 1260 + 1260 + 1260 = 6300 \] ### Final Answer: The total number of words that can be formed by writing down the letters of the word "CALCULATE," such that each word starts and ends with a consonant, is **6300**.
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