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The parallelogram is cut by two sets of ...

The parallelogram is cut by two sets of m lines parallel to its sides. The numbers parallelogram thus formed, is

A

`(.^(m)C_(2))^(2)`

B

`(.^(m+1)C_(2))^(2)`

C

`(.^(m+2)C_(2))^(2)`

D

None of these

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The correct Answer is:
To solve the problem of finding the number of parallelograms formed when a given parallelogram is cut by two sets of \( m \) lines parallel to its sides, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have a parallelogram that is cut by two sets of \( m \) lines. - One set of lines is parallel to one pair of sides, and the other set is parallel to the other pair of sides. 2. **Counting the Lines**: - For the lines parallel to one pair of sides, there are \( m \) lines plus the two original sides of the parallelogram. Therefore, the total number of lines in this direction is: \[ m + 2 \] - Similarly, for the lines parallel to the other pair of sides, we also have: \[ m + 2 \] 3. **Choosing Lines to Form Parallelograms**: - A parallelogram is formed by choosing 2 lines from the set of lines parallel to one pair of sides and 2 lines from the set of lines parallel to the other pair of sides. - The number of ways to choose 2 lines from \( m + 2 \) lines is given by the combination formula \( C(n, r) \), which is: \[ C(m + 2, 2) \] 4. **Calculating Total Parallelograms**: - Since we need to choose 2 lines from both sets, the total number of parallelograms formed is: \[ C(m + 2, 2) \times C(m + 2, 2) \] - This can be expressed as: \[ \left( C(m + 2, 2) \right)^2 \] 5. **Final Expression**: - Therefore, the total number of parallelograms formed is: \[ \left( C(m + 2, 2) \right)^2 \] ### Conclusion: The correct answer is \( C(m + 2, 2)^2 \).
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