Home
Class 12
MATHS
Statement-1: There are pge8 points in sp...

Statement-1: There are `pge8` points in space no four of which are in the same with exception of `q ge3` points which are in the same plane, then the number of planes each containing three points is `.^(p)C_(3)-.^(q)C_(3)`.
Statement-2: 3 non-collinear points alwasy determine unique plane.

A

Statement-1 is true, statement-2 is true, statement-2 is a correct explanation for statement-1

B

Statement-1 is true, statement-2 is true, statement-2 is not a correct explanation for statement-1

C

Statement-1 is true, statement-2 is false

D

Statement-1 is false, statement-2 is true

Text Solution

Verified by Experts

The correct Answer is:
D
Number of planes each containing three points
`=.^(p)C_(3)-.^(q)C_(3)+1`
`therefore`Statement-1 is false and statement-2 is always true.
Promotional Banner

Topper's Solved these Questions

  • PERMUTATIONS AND COMBINATIONS

    ARIHANT MATHS ENGLISH|Exercise Exercise (Subjective Type Questions)|16 Videos

  • PERMUTATIONS AND COMBINATIONS

    ARIHANT MATHS ENGLISH|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|28 Videos

  • PERMUTATIONS AND COMBINATIONS

    ARIHANT MATHS ENGLISH|Exercise Permutations and Combinations Exercise 5: Matching Type Questions|2 Videos

  • PARABOLA

    ARIHANT MATHS ENGLISH|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|36 Videos

  • PROBABILITY

    ARIHANT MATHS ENGLISH|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|54 Videos

Similar Questions

Explore conceptually related problems

There are 10 points in a plane, no three of which are in the same straight line, except 4 points, which are collinear. Find the number of lines obtained from the pairs of these points,

There are 15 points in a plane, no three of which are in a straight line except 4, all of which are in a straight line. The number of triangles that can be formed by using these 15 points is:

Out of 18 points in as plane, no three points are in the same straight line except five points which are collinear. The number of straight lines formed by joining them is

There are 15 points in a plane, no three of which are in the same straight line with the exception of 6, which are all in the same straight line. Find the number of i. straight lines formed, ii. number of triangles formed by joining these points.

If there are six straight lines in a plane, no two of which are parallel and no three of which pass through the same point, then find the number of points in which these lines intersect.

There are 12 points in a plane of which 5 are collinear. Except these five points no three are collinear, then

There are 16 points in a plane of which 6 points are collinear and no other 3 points are collinear.Then the number of quadrilaterals that can be formed by joining these points is

In a plane there are 8 points , no three of which are collinear .How many lines do the points determine ?

Three are 12 points in a plane, no of three of which are in the same straight line, except 5 points whoich are collinear. Find (i) the numbers of lines obtained from the pairs of these points. (ii) the numbers of triangles that can be formed with vertices as these points.

Coplanar points are the points that are in the same plane. Thus, Can 150 points be coplanar? Can 3 points be non-coplanar?