If `A ={ theta : 2cos^2 theta + sintheta <=2}` , and `B = {theta: pi/2<=theta<= (3pi)/2}` then the region for `(AnnB)` is _____

Explanation

To solve the problem, we need to find the region for \( A \setminus B \) given the sets \( A \) and \( B \).

### Step 1: Define the sets
- Set \( A = \{ \theta : 2 \cos^2 \theta + \sin \theta \leq 2 \} \)
- Set \( B = \{ \theta : \frac{\pi}{2} \leq \theta \leq \frac{3\pi}{2} \} \)

### Step 2: Solve the inequality for set \( A \)
We start with the inequality:
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