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If f(x)=(a-x^(n))^(1//n),"where a "gt 0"...

If `f(x)=(a-x^(n))^(1//n),"where a "gt 0" and "n in N`, then fof (x) is equal to

A

a

B

x

C

`x^(n)`

D

`a^(n)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find \( f(f(x)) \) given the function \( f(x) = (a - x^n)^{\frac{1}{n}} \), where \( a > 0 \) and \( n \in \mathbb{N} \). ### Step-by-step Solution: 1. **Identify the function**: We have \( f(x) = (a - x^n)^{\frac{1}{n}} \). 2. **Find \( f(f(x)) \)**: We need to compute \( f(f(x)) \). This means we will substitute \( f(x) \) into the function \( f \): \[ f(f(x)) = f((a - x^n)^{\frac{1}{n}}) \] 3. **Substitute \( f(x) \) into \( f \)**: Now, we replace \( x \) in \( f(x) \) with \( (a - x^n)^{\frac{1}{n}} \): \[ f(f(x)) = \left( a - \left( (a - x^n)^{\frac{1}{n}} \right)^n \right)^{\frac{1}{n}} \] 4. **Simplify the expression**: The term \( \left( (a - x^n)^{\frac{1}{n}} \right)^n \) simplifies to \( a - x^n \): \[ f(f(x)) = \left( a - (a - x^n) \right)^{\frac{1}{n}} \] 5. **Further simplify**: Now, simplifying \( a - (a - x^n) \): \[ f(f(x)) = \left( x^n \right)^{\frac{1}{n}} \] 6. **Final simplification**: The expression \( \left( x^n \right)^{\frac{1}{n}} \) simplifies to \( x \): \[ f(f(x)) = x \] ### Conclusion: Thus, the final result is: \[ f(f(x)) = x \]
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