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Two finite sets have m and n elements. T...

Two finite sets have m and n elements. The total number of subsets of the first set is 48 more than the total number of subsets of the second set. The value of m - n is

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To solve the problem, we need to find the difference \( m - n \) given that the total number of subsets of the first set (with \( m \) elements) is 48 more than the total number of subsets of the second set (with \( n \) elements). ### Step-by-step Solution: 1. **Understanding the number of subsets**: The number of subsets of a set with \( p \) elements is given by \( 2^p \). Therefore: - The number of subsets of the first set (with \( m \) elements) is \( 2^m \). - The number of subsets of the second set (with \( n \) elements) is \( 2^n \). 2. **Setting up the equation**: According to the problem, the total number of subsets of the first set is 48 more than that of the second set. This can be expressed mathematically as: \[ 2^m = 2^n + 48 \] 3. **Rearranging the equation**: We can rearrange the equation to isolate \( 2^m \): \[ 2^m - 2^n = 48 \] 4. **Factoring the left-hand side**: We can factor the left-hand side using the property of exponents: \[ 2^n(2^{m-n} - 1) = 48 \] 5. **Finding possible values**: Since \( 2^n \) must be a power of 2, we can test various values of \( n \) to find suitable values for \( 2^n \) that divide 48: - If \( n = 0 \): \( 2^0 = 1 \) → \( 1(2^{m-0} - 1) = 48 \) → \( 2^m - 1 = 48 \) → \( 2^m = 49 \) (not a power of 2) - If \( n = 1 \): \( 2^1 = 2 \) → \( 2(2^{m-1} - 1) = 48 \) → \( 2^{m-1} - 1 = 24 \) → \( 2^{m-1} = 25 \) (not a power of 2) - If \( n = 2 \): \( 2^2 = 4 \) → \( 4(2^{m-2} - 1) = 48 \) → \( 2^{m-2} - 1 = 12 \) → \( 2^{m-2} = 13 \) (not a power of 2) - If \( n = 3 \): \( 2^3 = 8 \) → \( 8(2^{m-3} - 1) = 48 \) → \( 2^{m-3} - 1 = 6 \) → \( 2^{m-3} = 7 \) (not a power of 2) - If \( n = 4 \): \( 2^4 = 16 \) → \( 16(2^{m-4} - 1) = 48 \) → \( 2^{m-4} - 1 = 3 \) → \( 2^{m-4} = 4 \) → \( m - 4 = 2 \) → \( m = 6 \) - If \( n = 5 \): \( 2^5 = 32 \) → \( 32(2^{m-5} - 1) = 48 \) → \( 2^{m-5} - 1 = 1 \) → \( 2^{m-5} = 2 \) → \( m - 5 = 1 \) → \( m = 6 \) 6. **Finding \( m - n \)**: From the calculations, we found \( m = 6 \) and \( n = 4 \). Therefore: \[ m - n = 6 - 4 = 2 \] ### Final Answer: The value of \( m - n \) is \( 2 \).

To solve the problem, we need to find the difference \( m - n \) given that the total number of subsets of the first set (with \( m \) elements) is 48 more than the total number of subsets of the second set (with \( n \) elements). ### Step-by-step Solution: 1. **Understanding the number of subsets**: The number of subsets of a set with \( p \) elements is given by \( 2^p \). Therefore: - The number of subsets of the first set (with \( m \) elements) is \( 2^m \). - The number of subsets of the second set (with \( n \) elements) is \( 2^n \). ...
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