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Let A and B be too sets containing four ...

Let A and B be too sets containing four and two elements respectively then the number of subsets of set `AxxB` having atleast 3 elements is

A

275

B

510

C

219

D

256

Text Solution

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The correct Answer is:
To solve the problem, we need to find the number of subsets of the Cartesian product of two sets \( A \) and \( B \) that have at least 3 elements. Let's break it down step by step. ### Step 1: Determine the cardinality of sets \( A \) and \( B \) Given: - Set \( A \) has 4 elements. - Set \( B \) has 2 elements. ### Step 2: Calculate the cardinality of the Cartesian product \( A \times B \) The number of elements in the Cartesian product \( A \times B \) is given by: \[ |A \times B| = |A| \times |B| = 4 \times 2 = 8 \] So, the set \( A \times B \) has 8 elements. ### Step 3: Calculate the total number of subsets of \( A \times B \) The total number of subsets of a set with \( n \) elements is given by \( 2^n \). Therefore, for \( A \times B \): \[ \text{Total subsets} = 2^8 = 256 \] ### Step 4: Calculate the number of subsets with fewer than 3 elements We need to find the number of subsets that have at least 3 elements. To do this, we first calculate the number of subsets with 0, 1, and 2 elements. 1. **Subsets with 0 elements**: \[ \binom{8}{0} = 1 \] 2. **Subsets with 1 element**: \[ \binom{8}{1} = 8 \] 3. **Subsets with 2 elements**: \[ \binom{8}{2} = \frac{8!}{2!(8-2)!} = \frac{8 \times 7}{2 \times 1} = 28 \] ### Step 5: Sum the subsets with fewer than 3 elements Now, we sum the subsets with 0, 1, and 2 elements: \[ \text{Total subsets with fewer than 3 elements} = \binom{8}{0} + \binom{8}{1} + \binom{8}{2} = 1 + 8 + 28 = 37 \] ### Step 6: Calculate the number of subsets with at least 3 elements To find the number of subsets with at least 3 elements, we subtract the number of subsets with fewer than 3 elements from the total number of subsets: \[ \text{Subsets with at least 3 elements} = \text{Total subsets} - \text{Subsets with fewer than 3 elements} \] \[ = 256 - 37 = 219 \] ### Final Answer The number of subsets of the set \( A \times B \) having at least 3 elements is **219**. ---

To solve the problem, we need to find the number of subsets of the Cartesian product of two sets \( A \) and \( B \) that have at least 3 elements. Let's break it down step by step. ### Step 1: Determine the cardinality of sets \( A \) and \( B \) Given: - Set \( A \) has 4 elements. - Set \( B \) has 2 elements. ### Step 2: Calculate the cardinality of the Cartesian product \( A \times B \) ...
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