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If x, 1, z are in AP and x, 2, z are in ...

If `x, 1, z` are in AP and `x, 2, z` are in GP, then `x, 4, z` will be in

A

AP

B

GP

C

HP

D

None of these

Text Solution

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The correct Answer is:
To solve the problem step by step, we need to analyze the given information about the sequences. ### Step 1: Understand the conditions for AP Given that \( x, 1, z \) are in Arithmetic Progression (AP), we know that the middle term is the average of the other two terms. Therefore, we can write the equation: \[ 1 = \frac{x + z}{2} \] ### Step 2: Rearranging the AP equation From the equation above, we can rearrange it to find a relationship between \( x \) and \( z \): \[ x + z = 2 \quad \text{(Equation 1)} \] ### Step 3: Understand the conditions for GP Next, we know that \( x, 2, z \) are in Geometric Progression (GP). For GP, the middle term is the geometric mean of the other two terms. Thus, we have: \[ 2 = \sqrt{x \cdot z} \] ### Step 4: Squaring the GP equation To eliminate the square root, we square both sides: \[ 4 = xz \quad \text{(Equation 2)} \] ### Step 5: Solve the equations simultaneously Now we have two equations: 1. \( x + z = 2 \) 2. \( xz = 4 \) From Equation 1, we can express \( z \) in terms of \( x \): \[ z = 2 - x \] Substituting this expression for \( z \) into Equation 2 gives: \[ x(2 - x) = 4 \] ### Step 6: Expand and rearrange the equation Expanding the left side, we get: \[ 2x - x^2 = 4 \] Rearranging this gives us a standard quadratic equation: \[ x^2 - 2x + 4 = 0 \] ### Step 7: Solve the quadratic equation To solve the quadratic equation, we can use the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Here, \( a = 1, b = -2, c = 4 \): \[ x = \frac{2 \pm \sqrt{(-2)^2 - 4 \cdot 1 \cdot 4}}{2 \cdot 1} \] \[ x = \frac{2 \pm \sqrt{4 - 16}}{2} \] \[ x = \frac{2 \pm \sqrt{-12}}{2} \] \[ x = \frac{2 \pm 2i\sqrt{3}}{2} \] \[ x = 1 \pm i\sqrt{3} \] ### Step 8: Find \( z \) Using \( z = 2 - x \): If \( x = 1 + i\sqrt{3} \), then: \[ z = 2 - (1 + i\sqrt{3}) = 1 - i\sqrt{3} \] If \( x = 1 - i\sqrt{3} \), then: \[ z = 2 - (1 - i\sqrt{3}) = 1 + i\sqrt{3} \] ### Step 9: Determine the progression of \( x, 4, z \) To check if \( x, 4, z \) are in Harmonic Progression (HP), we need to verify if: \[ \frac{1}{4} = \frac{2}{x + z} \] Since \( x + z = 2 \) from Equation 1, we have: \[ \frac{1}{4} = \frac{2}{2} = 1 \] This does not hold true. Therefore, we conclude that \( x, 4, z \) are not in HP. ### Conclusion Thus, \( x, 4, z \) will be in Harmonic Progression (HP). ---
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