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Let alpha and beta be two positive real...

Let `alpha` and `beta` be two positive real numbers. Suppose `A_1, A_2` are two arithmetic means; `G_1 ,G_2` are tow geometrie means and `H_1 H_2` are two harmonic means between `alpha` and `beta`, then

A

`A_(1)H_(2)`

B

`A_(2)H_(1)`

C

`G_(1)G_(2)`

D

None of these

Text Solution

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The correct Answer is:
To solve the problem, we need to find the relationships between the arithmetic means \( A_1, A_2 \), geometric means \( G_1, G_2 \), and harmonic means \( H_1, H_2 \) given two positive real numbers \( \alpha \) and \( \beta \). ### Step 1: Find the Arithmetic Means \( A_1 \) and \( A_2 \) The two arithmetic means \( A_1 \) and \( A_2 \) between \( \alpha \) and \( \beta \) can be expressed as: \[ A_1 = \alpha + \frac{1}{3}(\beta - \alpha) = \frac{2\alpha + \beta}{3} \] \[ A_2 = \beta - \frac{1}{3}(\beta - \alpha) = \frac{\alpha + 2\beta}{3} \] ### Step 2: Calculate \( A_1 + A_2 \) Now, we can calculate \( A_1 + A_2 \): \[ A_1 + A_2 = \frac{2\alpha + \beta}{3} + \frac{\alpha + 2\beta}{3} = \frac{3\alpha + 3\beta}{3} = \alpha + \beta \] This gives us our first equation: \[ A_1 + A_2 = \alpha + \beta \quad \text{(Equation 1)} \] ### Step 3: Find the Geometric Means \( G_1 \) and \( G_2 \) The geometric means \( G_1 \) and \( G_2 \) can be expressed as: \[ G_1 = \sqrt{\alpha \cdot \beta} \] \[ G_2 = \sqrt{\alpha \cdot \beta} \] Thus, we have: \[ G_1 \cdot G_2 = \sqrt{\alpha \cdot \beta} \cdot \sqrt{\alpha \cdot \beta} = \alpha \cdot \beta \] This gives us our second equation: \[ G_1 \cdot G_2 = \alpha \cdot \beta \quad \text{(Equation 2)} \] ### Step 4: Find the Harmonic Means \( H_1 \) and \( H_2 \) The harmonic means \( H_1 \) and \( H_2 \) can be expressed as: \[ \frac{1}{H_1} = \frac{1}{2} \left( \frac{1}{\alpha} + \frac{1}{\beta} \right) \quad \Rightarrow \quad H_1 = \frac{2\alpha\beta}{\alpha + \beta} \] \[ \frac{1}{H_2} = \frac{1}{2} \left( \frac{1}{\alpha} + \frac{1}{\beta} \right) \quad \Rightarrow \quad H_2 = \frac{2\alpha\beta}{\alpha + \beta} \] ### Step 5: Calculate \( H_1 + H_2 \) and \( H_1 \cdot H_2 \) Calculating \( H_1 + H_2 \): \[ H_1 + H_2 = \frac{2\alpha\beta}{\alpha + \beta} + \frac{2\alpha\beta}{\alpha + \beta} = \frac{4\alpha\beta}{\alpha + \beta} \] Calculating \( H_1 \cdot H_2 \): \[ H_1 \cdot H_2 = \left( \frac{2\alpha\beta}{\alpha + \beta} \right) \cdot \left( \frac{2\alpha\beta}{\alpha + \beta} \right) = \frac{4\alpha^2\beta^2}{(\alpha + \beta)^2} \] ### Step 6: Establish the Relationship Now we have: - \( A_1 + A_2 = \alpha + \beta \) - \( G_1 \cdot G_2 = \alpha \cdot \beta \) - \( H_1 + H_2 = \frac{4\alpha\beta}{\alpha + \beta} \) - \( H_1 \cdot H_2 = \frac{4\alpha^2\beta^2}{(\alpha + \beta)^2} \) ### Conclusion From the above calculations, we can conclude that: - The relationship between the arithmetic, geometric, and harmonic means can be expressed as: \[ \frac{A_1 + A_2}{H_1 + H_2} = \frac{G_1 \cdot G_2}{H_1 \cdot H_2} \]
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