The sequence of odd natural numbers is divided into groups `1,3,5,7,9,11,"…."` and so on. Show that the sum of the numbers in nth group is `n^(3)`.

Explanation

To show that the sum of the numbers in the nth group of odd natural numbers is \( n^3 \), we will follow these steps:

### Step 1: Identify the nth group of odd natural numbers
The sequence of odd natural numbers is \( 1, 3, 5, 7, 9, 11, \ldots \). The first group contains 1 element, the second group contains 2 elements, the third group contains 3 elements, and so on. Thus, the nth group contains \( n \) elements.

### Step 2: Determine the first and last elements of the nth group
The first element of the nth group can be found using the formula:
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