The mwan and variance of a binomial variable X are and 1, respectivily. Find the probability that X takes values greater than .

If the mean and the variance of a binomial variable X are 2 and 1 respectively, then the probability that X takes a value greater than one is equal to:

If the mean and variance of a binomial variable X are 2 and 1 respectively. Find P(X >1) .

If the mean and variance of a binomial variate X are 7/3a n d(14)/9 respectively. Then probability that X takes values 6 or 7 is equal to 1/(729) 2. 5/(729) 3. 7/(729) 4. (13)/(729) 5. (15)/(729)

The mean and variance of a binomial distribution are 4 and 4/3 respectively, find P(X=1)dot

Mean and Variance of a binomial variance are 4 and 4/3 respectively then P(X geq1) will be

The mean and variance of a Binomial variate are 2.4 and 1.44 respectively. Find the parameters, P(X=2) and P(1 lt X le4) .

If the mean and the variance of a binomial distribution are 2 and 1 respectively , then the probability of atleast one success is

If the sum and the product of the mean and variance of a Binomial Distribution are 1-8 and 0.8 respectively, find the probability distribution and the probability of at least one success

The mean and variance of a binomial distribution are 4 and 3 respectively. Fix the distribution and find P(X ge 1) .

The mean and variance of a binomial variance with parameters n and p are 16 and 8 respectively. Find P(X=0)