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If A and B are two events such that P(A)...

If A and B are two events such that `P(A)gt0 and P(B)!=1,` then `P((overline(A))/(B))` is equal to

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To solve the problem of finding \( P(\overline{A} | B) \), we can use the definition of conditional probability. Let's go through the solution step by step. ### Step-by-Step Solution: 1. **Understanding Conditional Probability**: The conditional probability of event \( A \) given event \( B \) is defined as: \[ P(A | B) = \frac{P(A \cap B)}{P(B)} \] Similarly, for \( \overline{A} \) (the complement of \( A \)), we have: \[ P(\overline{A} | B) = \frac{P(\overline{A} \cap B)}{P(B)} \] 2. **Using the Complement Rule**: We know that: \[ P(A \cap B) + P(\overline{A} \cap B) = P(B) \] This means we can express \( P(\overline{A} \cap B) \) as: \[ P(\overline{A} \cap B) = P(B) - P(A \cap B) \] 3. **Expressing \( P(A \cap B) \)**: From the definition of conditional probability, we can express \( P(A \cap B) \) as: \[ P(A \cap B) = P(A | B) \cdot P(B) \] 4. **Substituting Back**: Now, substituting \( P(A \cap B) \) back into the equation for \( P(\overline{A} \cap B) \): \[ P(\overline{A} \cap B) = P(B) - P(A | B) \cdot P(B) \] This simplifies to: \[ P(\overline{A} \cap B) = P(B)(1 - P(A | B)) \] 5. **Finding \( P(\overline{A} | B) \)**: Now, substituting \( P(\overline{A} \cap B) \) into the formula for \( P(\overline{A} | B) \): \[ P(\overline{A} | B) = \frac{P(\overline{A} \cap B)}{P(B)} = \frac{P(B)(1 - P(A | B))}{P(B)} = 1 - P(A | B) \] 6. **Final Result**: Therefore, we conclude that: \[ P(\overline{A} | B) = 1 - P(A | B) \]
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