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A chess game between two grandmasters X ...

A chess game between two grandmasters X and Y is won by whoever first wins a total of two games. X's chances of winning or loosing any perticular game are a, b and c, respectively. The games are independent and a+b+c=1.
The probability that Y wins the match after the 4th game, is

A

`(a^(a+2c))/((a+c)^3)`

B

`(a^3)/((a+c)^3)`

C

`(a^2(a+3c))/((a+c)^3)`

D

`(c^3)/((a+c)^3)`

Text Solution

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The correct Answer is:
(c)
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ARIHANT MATHS ENGLISH-PROBABILITY-Exercise (Passage Based Questions)
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