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A JEE aspirant estimates that she will b...

A JEE aspirant estimates that she will be successful with an 80 percent chance if she studies 10 hours per day, with a 60 percent chance if she studies 7 hours per day and with 40 percent chance if she studies 4 hours per day. She further believes that she will study 10 hours, 7 hours and 4 hours per day with probabilities 0.1, 0.2 and 0.7 respectively. Given that she does not achieve success, the chance she studied for 4 hours is?

A

`(15)/(26)`

B

`(17)/(26)`

C

`(19)/(26)`

D

`(21)/(26)`

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The correct Answer is:
To solve the problem step by step, we will use the concepts of conditional probability and Bayes' theorem. ### Step 1: Define the events Let: - \( A_1 \): Event that she studies for 10 hours. - \( A_2 \): Event that she studies for 7 hours. - \( A_3 \): Event that she studies for 4 hours. - \( B \): Event that she does not achieve success. From the problem, we know: - \( P(A_1) = 0.1 \) - \( P(A_2) = 0.2 \) - \( P(A_3) = 0.7 \) ### Step 2: Calculate the probabilities of not achieving success The probabilities of not achieving success given the hours studied are: - \( P(B | A_1) = 1 - 0.8 = 0.2 \) (for 10 hours) - \( P(B | A_2) = 1 - 0.6 = 0.4 \) (for 7 hours) - \( P(B | A_3) = 1 - 0.4 = 0.6 \) (for 4 hours) ### Step 3: Calculate the total probability of not achieving success Using the law of total probability: \[ P(B) = P(B | A_1)P(A_1) + P(B | A_2)P(A_2) + P(B | A_3)P(A_3) \] Substituting the values: \[ P(B) = (0.2)(0.1) + (0.4)(0.2) + (0.6)(0.7) \] Calculating each term: - \( (0.2)(0.1) = 0.02 \) - \( (0.4)(0.2) = 0.08 \) - \( (0.6)(0.7) = 0.42 \) Adding these: \[ P(B) = 0.02 + 0.08 + 0.42 = 0.52 \] ### Step 4: Calculate the conditional probability of studying for 4 hours given that she did not achieve success We want to find \( P(A_3 | B) \). By Bayes' theorem: \[ P(A_3 | B) = \frac{P(B | A_3)P(A_3)}{P(B)} \] Substituting the values: \[ P(A_3 | B) = \frac{P(B | A_3)P(A_3)}{P(B)} = \frac{(0.6)(0.7)}{0.52} \] Calculating the numerator: \[ (0.6)(0.7) = 0.42 \] Thus: \[ P(A_3 | B) = \frac{0.42}{0.52} \] ### Step 5: Simplify the fraction To simplify \( \frac{0.42}{0.52} \): \[ P(A_3 | B) = \frac{42}{52} = \frac{21}{26} \] ### Final Answer The probability that she studied for 4 hours given that she did not achieve success is \( \frac{21}{26} \). ---
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A JEE aspirant estimates that she will be successful with an 80 percent chance if she studies 10 hours per day, with a 60 percent chance if she studies 7 hours per day and with 40 percent chance if she studies 4 hours per day. She further believes that she will study 10 hours, 7 hours and 4 hours per day with probabilities 0.1, 0.2 and 0.7 respectively. Given that she will achieve success, the chance she studied for 4 hours is?

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ARIHANT MATHS ENGLISH-PROBABILITY-Exercise (Passage Based Questions)
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  2. There are n students in a class. Ler P(Elambda) be the probability tha...

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  9. Suppose E1, E2 and E3 be three mutually exclusive events such that P(E...

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  10. Suppose E1, E2 and E3 be three mutually exclusive events such that P(E...

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  11. Suppose E1, E2 and E3 be three mutually exclusive events such that P(E...

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  12. Let A = {1, 2, 3}, B = {2, 4} and R = {(1, 2), (2, 2), (2, 4), (3, 4)}...

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  13. Let A={1, ,2, 3} and B={-2, -1, 0, 1, 2,3}. The probability of incre...

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  14. Let A={1, ,2, 3} and B={-2, -1, 0, 1, 2,3}. The probability of incre...

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  15. A random variable X takes the values 0,1,2,3,..., with prbability PX(=...

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  16. A random variable X takes values 0, 1, 2, 3,… with probability proport...

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  17. A random variable X takes values 0, 1, 2,...... with probability propo...

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  18. Let n=10lambda+r", where " lambda,rinN, 0lerle9. A number a is chosen...

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