If m things are distributed among a men and b women, then show that the chances that the number of things received by men is odd are given by `((b+a)^(m)-(b-a)^(m))/(2(b+a)^(m))`

If m things are distributed among a men and b women. Then the probability that number of things received by men is odd is

If 25 identical things be distributed among 5 person then The number of ways each receives atleast one is

Number of ways in which 25 identical things be distributed among five persons if each gets odd number of things is

m women and n men are too be seated in a row so that no two men sit together. If mgtn then show that the number of wys in which they can be seated is (m!(m+1)!)/((m-n+1)!)

m women and n men are too be seated in a row so that no two men sit together. If mgtn then show that the number of wys in which they can be seated is (m!(m+1)!)/((m-n+1)!)

m men and n women are to be seated in a row so that no two women sit together. If (m>n) then show that the number of ways in which they can be seated as (m!(m+1)!)/((m-n+1)!) .

If the A.M between a and b is m times their H.M then a:b is

If a is the A.M. between b and c, b the G.M. between a and c, then show that 1/a,1/c,1/b are in A.P.

If n men and m women are to be seated in a row so that no two women sit together . If ngtm , then show that number of ways in which they can be seated is (n!(n+1)!)/((n-m+1)!)

Number of ways in which 30 identical things are distributed among six persons is a .^17C_5 if each gets odd number of things b .^16C_11 if each gets odd number of things c .^14C_5 if each gets even number of things (excluding 0) d .^15C_10 if each gets even number of things (excluding 0)