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One ticket is selected at random from 50 tickets numbered 00, 01, 02, ... , 49. Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, equals (1) 1/14 (2) 1/7 (3) 5/14 (4) 1/50

A

`(1)/(50)`

B

`(1)/(14)`

C

`(1)/(7)`

D

`(5)/(14)`

Text Solution

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The correct Answer is:
B
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